(x-3)(x+3)=x^2-9

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Solution for (x-3)(x+3)=x^2-9 equation:


Simplifying
(x + -3)(x + 3) = x2 + -9

Reorder the terms:
(-3 + x)(x + 3) = x2 + -9

Reorder the terms:
(-3 + x)(3 + x) = x2 + -9

Multiply (-3 + x) * (3 + x)
(-3(3 + x) + x(3 + x)) = x2 + -9
((3 * -3 + x * -3) + x(3 + x)) = x2 + -9
((-9 + -3x) + x(3 + x)) = x2 + -9
(-9 + -3x + (3 * x + x * x)) = x2 + -9
(-9 + -3x + (3x + x2)) = x2 + -9

Combine like terms: -3x + 3x = 0
(-9 + 0 + x2) = x2 + -9
(-9 + x2) = x2 + -9

Reorder the terms:
-9 + x2 = -9 + x2

Add '9' to each side of the equation.
-9 + 9 + x2 = -9 + 9 + x2

Combine like terms: -9 + 9 = 0
0 + x2 = -9 + 9 + x2
x2 = -9 + 9 + x2

Combine like terms: -9 + 9 = 0
x2 = 0 + x2
x2 = x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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